Best Buy's Discounting the Latest iPad Pro by $100

Best Buy's Discounting the Latest iPad Pro by $100

Prices start at $549.99.

If you're one of the many people out there with a particular fondness of all kinds of gadgety tech stuff, this one might be your kind of thing.

Best Buy is currently discounting the price of Apple's latest (2017) iPad Pro by $100. That brings the price down to a much more reasonable $549.99.

That price is specifically on the 64GB 10.5" WiFi version of the 2017 iPad Pro, by the way. That one is available in Gold, Rose GOld, Silver or Space Gray on the Best Buy site. The 12.9" iPad Pro is also discounted, but that one will still cost you a cool $700.

It's generally pretty rare to see discounts on Apple products so when they do come along, they're always welcome. That doesn't make them cheap by any stretch of the imagination, just a little better value.

iPad Pro (10.5" 2017 model) for $549.99 from Best Buy

Sometimes we include links to online retail stores. If you click on one and make a purchase we may receive a small commission. See our terms & conditions.

Jamie Wallace

Contributor

Jamie is the Commerce Editor for Gamer Network and can usually be found writing about games, tech and his belief that there were never enough Jet Set Radios.

Related articles

Eric's Farewell | Off to Find a New Challenger

It's time for us to move on, but we'll carry USG with us wherever we go.

Mat's Farewell | The Truth Has Not Vanished Into Darkness

This isn't the real ending, is it? Can't be.

Press Start to Continue

A look back on what we tried to accomplish at USgamer, and the work still to be done.

You may also like

Kat, Mat, and Eric's Top 10 Games of 2020

Our favorites of the year, from those who remain.

USG's Top 20 Games of 2020

From thirsty gods to avaricious raccoons, these were our favorite games in 2020.

USG Game of the Year 2020: Hades Isn't Just About Escaping Home, But Rebuilding It

This Greek myth feels like the culmination of everything Supergiant Games has created thus far.